Base | Representation |
---|---|
bin | 11101110010101000000010… |
… | …111011010001010000101000 |
3 | 122011220121111212010111202001 |
4 | 131302220002323101100220 |
5 | 114133132203241022100 |
6 | 1142354453514020344 |
7 | 36412023160343611 |
oct | 3562500273212050 |
9 | 564817455114661 |
10 | 131022321423400 |
11 | 38825288775980 |
12 | 128410064176b4 |
13 | 5815476161a64 |
14 | 244d72ad34c08 |
15 | 10232d077ed6a |
hex | 772a02ed1428 |
131022321423400 has 192 divisors, whose sum is σ = 333378415272960. Its totient is φ = 47492892000000.
The previous prime is 131022321423391. The next prime is 131022321423403. The reversal of 131022321423400 is 4324123220131.
It is a super-2 number, since 2×1310223214234002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131022321423403) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1817421355 + ... + 1817493445.
It is an arithmetic number, because the mean of its divisors is an integer number (1736345912880).
Almost surely, 2131022321423400 is an apocalyptic number.
131022321423400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131022321423400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166689207636480).
131022321423400 is an abundant number, since it is smaller than the sum of its proper divisors (202356093849560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131022321423400 is a wasteful number, since it uses less digits than its factorization.
131022321423400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74736 (or 74727 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131022321423400 its reverse (4324123220131), we get a palindrome (135346444643531).
The spelling of 131022321423400 in words is "one hundred thirty-one trillion, twenty-two billion, three hundred twenty-one million, four hundred twenty-three thousand, four hundred".
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