Base | Representation |
---|---|
bin | 11000011001111010… |
… | …00011001100000001 |
3 | 1020211010011100211202 |
4 | 30030331003030001 |
5 | 203313132413241 |
6 | 10004042150545 |
7 | 642454065023 |
oct | 141475031401 |
9 | 36733140752 |
10 | 13102232321 |
11 | 5613961082 |
12 | 2657ab2455 |
13 | 130a6175b9 |
14 | 8c417c013 |
15 | 51a3e7d9b |
hex | 30cf43301 |
13102232321 has 2 divisors, whose sum is σ = 13102232322. Its totient is φ = 13102232320.
The previous prime is 13102232303. The next prime is 13102232383. The reversal of 13102232321 is 12323220131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8787187600 + 4315044721 = 93740^2 + 65689^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102232321 - 222 = 13098038017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102232293 and 13102232302.
It is not a weakly prime, because it can be changed into another prime (13102232921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551116160 + 6551116161.
It is an arithmetic number, because the mean of its divisors is an integer number (6551116161).
Almost surely, 213102232321 is an apocalyptic number.
It is an amenable number.
13102232321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102232321 is an equidigital number, since it uses as much as digits as its factorization.
13102232321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13102232321 its reverse (12323220131), we get a palindrome (25425452452).
The spelling of 13102232321 in words is "thirteen billion, one hundred two million, two hundred thirty-two thousand, three hundred twenty-one".
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