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1310224132114 = 22399273077143
BaseRepresentation
bin10011000100001111011…
…100011010100000010010
311122020220202212011210221
4103010033130122200102
5132431314334211424
62441524134143254
7163442401236622
oct23041734324022
94566822764727
101310224132114
11465732401a57
12191b1b4b1b2a
139672736b061
14475b53b2882
15241368079e4
hex1310f71a812

1310224132114 has 8 divisors (see below), whose sum is σ = 1966155436800. Its totient is φ = 654838986516.

The previous prime is 1310224132103. The next prime is 1310224132117. The reversal of 1310224132114 is 4112314220131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13102241321142 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1310224132117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136533774 + ... + 136543369.

It is an arithmetic number, because the mean of its divisors is an integer number (245769429600).

Almost surely, 21310224132114 is an apocalyptic number.

1310224132114 is a deficient number, since it is larger than the sum of its proper divisors (655931304686).

1310224132114 is a wasteful number, since it uses less digits than its factorization.

1310224132114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 273079544.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1310224132114 its reverse (4112314220131), we get a palindrome (5422538352245).

The spelling of 1310224132114 in words is "one trillion, three hundred ten billion, two hundred twenty-four million, one hundred thirty-two thousand, one hundred fourteen".

Divisors: 1 2 2399 4798 273077143 546154286 655112066057 1310224132114