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1310230421413 = 2714834798603
BaseRepresentation
bin10011000100001111110…
…100011001111110100101
311122020221012200201002221
4103010033310121332211
5132431322441441123
62441524521032341
7163442505553024
oct23041764317645
94566835621087
101310230421413
11465735a08221
12191b216256b1
1396728760934
14475b616c8bb
152413714b25d
hex1310fd19fa5

1310230421413 has 4 divisors (see below), whose sum is σ = 1315065220288. Its totient is φ = 1305395622540.

The previous prime is 1310230421327. The next prime is 1310230421443. The reversal of 1310230421413 is 3141240320131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310230421413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310230421443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2417399031 + ... + 2417399572.

It is an arithmetic number, because the mean of its divisors is an integer number (328766305072).

Almost surely, 21310230421413 is an apocalyptic number.

It is an amenable number.

1310230421413 is a deficient number, since it is larger than the sum of its proper divisors (4834798875).

1310230421413 is an equidigital number, since it uses as much as digits as its factorization.

1310230421413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4834798874.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1310230421413 its reverse (3141240320131), we get a palindrome (4451470741544).

The spelling of 1310230421413 in words is "one trillion, three hundred ten billion, two hundred thirty million, four hundred twenty-one thousand, four hundred thirteen".

Divisors: 1 271 4834798603 1310230421413