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131023111031102 = 265511555515551
BaseRepresentation
bin11101110010101000110001…
…111111011000100100111110
3122011220200112212220201212202
4131302220301333120210332
5114133140312410443402
61142355104122031502
736412051556035103
oct3562506177304476
9564820485821782
10131023111031102
1138825653458924
12128411a6948592
135815570916654
14244d7a3b56aaa
151023329c52b02
hex772a31fd893e

131023111031102 has 4 divisors (see below), whose sum is σ = 196534666546656. Its totient is φ = 65511555515550.

The previous prime is 131023111031051. The next prime is 131023111031107. The reversal of 131023111031102 is 201130111320131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1310231110311022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131023111031107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755777757774 + ... + 32755777757777.

It is an arithmetic number, because the mean of its divisors is an integer number (49133666636664).

Almost surely, 2131023111031102 is an apocalyptic number.

131023111031102 is a deficient number, since it is larger than the sum of its proper divisors (65511555515554).

131023111031102 is an equidigital number, since it uses as much as digits as its factorization.

131023111031102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65511555515553.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 131023111031102 its reverse (201130111320131), we get a palindrome (332153222351233).

The spelling of 131023111031102 in words is "one hundred thirty-one trillion, twenty-three billion, one hundred eleven million, thirty-one thousand, one hundred two".

Divisors: 1 2 65511555515551 131023111031102