Base | Representation |
---|---|
bin | 11101110010101000110010… |
… | …101101000101110111111001 |
3 | 122011220200120201110111002221 |
4 | 131302220302231011313321 |
5 | 114133140323442404423 |
6 | 1142355105230524041 |
7 | 36412052062631062 |
oct | 3562506255056771 |
9 | 564820521414087 |
10 | 131023123013113 |
11 | 3882565a1a2111 |
12 | 128411aa966621 |
13 | 58155732503b6 |
14 | 244d7a5595569 |
15 | 102332ad1ce5d |
hex | 772a32b45df9 |
131023123013113 has 4 divisors (see below), whose sum is σ = 131032701440640. Its totient is φ = 131013544585588.
The previous prime is 131023123013021. The next prime is 131023123013137. The reversal of 131023123013113 is 311310321320131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131023123013113 - 245 = 95838750924281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131023123013173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4789193245 + ... + 4789220602.
It is an arithmetic number, because the mean of its divisors is an integer number (32758175360160).
Almost surely, 2131023123013113 is an apocalyptic number.
It is an amenable number.
131023123013113 is a deficient number, since it is larger than the sum of its proper divisors (9578427527).
131023123013113 is an equidigital number, since it uses as much as digits as its factorization.
131023123013113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9578427526.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 131023123013113 its reverse (311310321320131), we get a palindrome (442333444333244).
The spelling of 131023123013113 in words is "one hundred thirty-one trillion, twenty-three billion, one hundred twenty-three million, thirteen thousand, one hundred thirteen".
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