Base | Representation |
---|---|
bin | 1011111010101001111100… |
… | …1001100011010011011011 |
3 | 1201101120101020021001110002 |
4 | 2332222133021203103123 |
5 | 3204132023001142133 |
6 | 43511042312243215 |
7 | 2521416466161233 |
oct | 276523711432333 |
9 | 51346336231402 |
10 | 13102320334043 |
11 | 41a1732285136 |
12 | 15773986a050b |
13 | 74070b10c485 |
14 | 3342272c8cc3 |
15 | 17ac4c45cce8 |
hex | bea9f2634db |
13102320334043 has 2 divisors, whose sum is σ = 13102320334044. Its totient is φ = 13102320334042.
The previous prime is 13102320333979. The next prime is 13102320334067. The reversal of 13102320334043 is 34043302320131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102320334043 - 26 = 13102320333979 is a prime.
It is a super-2 number, since 2×131023203340432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13102320333997 and 13102320334015.
It is not a weakly prime, because it can be changed into another prime (13102320334643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551160167021 + 6551160167022.
It is an arithmetic number, because the mean of its divisors is an integer number (6551160167022).
Almost surely, 213102320334043 is an apocalyptic number.
13102320334043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102320334043 is an equidigital number, since it uses as much as digits as its factorization.
13102320334043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 13102320334043 its reverse (34043302320131), we get a palindrome (47145622654174).
The spelling of 13102320334043 in words is "thirteen trillion, one hundred two billion, three hundred twenty million, three hundred thirty-four thousand, forty-three".
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