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1310232122113 is a prime number
BaseRepresentation
bin10011000100001111111…
…010111001001100000001
311122020221022220010000211
4103010033322321030001
5132431323410401423
62441525021314121
7163442526165235
oct23041772711401
94566838803024
101310232122113
11465736969a62
12191b22105941
1396728c07a75
14475b64925c5
152413738510d
hex1310feb9301

1310232122113 has 2 divisors, whose sum is σ = 1310232122114. Its totient is φ = 1310232122112.

The previous prime is 1310232122099. The next prime is 1310232122117. The reversal of 1310232122113 is 3112212320131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 857340809329 + 452891312784 = 925927^2 + 672972^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310232122113 - 229 = 1309695251201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310232122117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655116061056 + 655116061057.

It is an arithmetic number, because the mean of its divisors is an integer number (655116061057).

Almost surely, 21310232122113 is an apocalyptic number.

It is an amenable number.

1310232122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310232122113 is an equidigital number, since it uses as much as digits as its factorization.

1310232122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1310232122113 its reverse (3112212320131), we get a palindrome (4422444442244).

The spelling of 1310232122113 in words is "one trillion, three hundred ten billion, two hundred thirty-two million, one hundred twenty-two thousand, one hundred thirteen".