Base | Representation |
---|---|
bin | 10011000100001111111… |
… | …111011101101001110001 |
3 | 11122020221102010222021211 |
4 | 103010033333131221301 |
5 | 132431324212220144 |
6 | 2441525103120121 |
7 | 163442542314613 |
oct | 23041777355161 |
9 | 4566842128254 |
10 | 1310233320049 |
11 | 465737607a95 |
12 | 191b225a3041 |
13 | 967292370c4 |
14 | 475b66c4db3 |
15 | 24137520034 |
hex | 1310ffdda71 |
1310233320049 has 2 divisors, whose sum is σ = 1310233320050. Its totient is φ = 1310233320048.
The previous prime is 1310233320043. The next prime is 1310233320167. The reversal of 1310233320049 is 9400233320131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1128838251024 + 181395069025 = 1062468^2 + 425905^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310233320049 - 25 = 1310233320017 is a prime.
It is a super-2 number, since 2×13102333200492 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1310233320049.
It is not a weakly prime, because it can be changed into another prime (1310233320043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655116660024 + 655116660025.
It is an arithmetic number, because the mean of its divisors is an integer number (655116660025).
Almost surely, 21310233320049 is an apocalyptic number.
It is an amenable number.
1310233320049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310233320049 is an equidigital number, since it uses as much as digits as its factorization.
1310233320049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 1310233320049 in words is "one trillion, three hundred ten billion, two hundred thirty-three million, three hundred twenty thousand, forty-nine".
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