Base | Representation |
---|---|
bin | 11101110010101000111111… |
… | …101001111110011100001001 |
3 | 122011220201010212022210201221 |
4 | 131302220333221332130021 |
5 | 114133141300104100131 |
6 | 1142355142552042041 |
7 | 36412060341554500 |
oct | 3562507751763411 |
9 | 564821125283657 |
10 | 131023340300041 |
11 | 38825760911a92 |
12 | 1284124b693321 |
13 | 58155a927ac47 |
14 | 244d7c6397837 |
15 | 102333ee3e411 |
hex | 772a3fa7e709 |
131023340300041 has 24 divisors (see below), whose sum is σ = 159277959477504. Its totient is φ = 107263244309760.
The previous prime is 131023340299981. The next prime is 131023340300077. The reversal of 131023340300041 is 140003043320131.
It is not a de Polignac number, because 131023340300041 - 215 = 131023340267273 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131023340299979 and 131023340300015.
It is not an unprimeable number, because it can be changed into a prime (131023340000041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 85614865 + ... + 87131806.
It is an arithmetic number, because the mean of its divisors is an integer number (6636581644896).
Almost surely, 2131023340300041 is an apocalyptic number.
It is an amenable number.
131023340300041 is a deficient number, since it is larger than the sum of its proper divisors (28254619177463).
131023340300041 is a wasteful number, since it uses less digits than its factorization.
131023340300041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172747381 (or 172747374 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131023340300041 its reverse (140003043320131), we get a palindrome (271026383620172).
The spelling of 131023340300041 in words is "one hundred thirty-one trillion, twenty-three billion, three hundred forty million, three hundred thousand, forty-one".
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