Base | Representation |
---|---|
bin | 111101000000110011… |
… | …0110001110010011111 |
3 | 110112012020201122102210 |
4 | 1322001212301302133 |
5 | 4121314000221101 |
6 | 140105155051503 |
7 | 12315611623314 |
oct | 1720146616237 |
9 | 415166648383 |
10 | 131023445151 |
11 | 50626356675 |
12 | 214875a0b93 |
13 | c480c30291 |
14 | 64ad39ad0b |
15 | 361cb267d6 |
hex | 1e819b1c9f |
131023445151 has 8 divisors (see below), whose sum is σ = 174699926064. Its totient is φ = 87347963840.
The previous prime is 131023445129. The next prime is 131023445159. The reversal of 131023445151 is 151544320131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131023445151 - 29 = 131023444639 is a prime.
It is a super-3 number, since 3×1310234451513 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131023445159) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145171 + ... + 532091.
It is an arithmetic number, because the mean of its divisors is an integer number (21837490758).
Almost surely, 2131023445151 is an apocalyptic number.
131023445151 is a deficient number, since it is larger than the sum of its proper divisors (43676480913).
131023445151 is a wasteful number, since it uses less digits than its factorization.
131023445151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 499801.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 131023445151 its reverse (151544320131), we get a palindrome (282567765282).
The spelling of 131023445151 in words is "one hundred thirty-one billion, twenty-three million, four hundred forty-five thousand, one hundred fifty-one".
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