Base | Representation |
---|---|
bin | 111101000000110100… |
… | …1011011101111101011 |
3 | 110112012022001000100202 |
4 | 1322001221123233223 |
5 | 4121314140010131 |
6 | 140105222022415 |
7 | 12315620553011 |
oct | 1720151335753 |
9 | 415168030322 |
10 | 131024141291 |
11 | 5062679169a |
12 | 21487877a0b |
13 | c4811150b4 |
14 | 64ad4dc8b1 |
15 | 361cc12bcb |
hex | 1e81a5bbeb |
131024141291 has 2 divisors, whose sum is σ = 131024141292. Its totient is φ = 131024141290.
The previous prime is 131024141267. The next prime is 131024141309. The reversal of 131024141291 is 192141420131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131024141291 - 222 = 131019946987 is a prime.
It is a super-2 number, since 2×1310241412912 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (131024141251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65512070645 + 65512070646.
It is an arithmetic number, because the mean of its divisors is an integer number (65512070646).
Almost surely, 2131024141291 is an apocalyptic number.
131024141291 is a deficient number, since it is larger than the sum of its proper divisors (1).
131024141291 is an equidigital number, since it uses as much as digits as its factorization.
131024141291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 131024141291 in words is "one hundred thirty-one billion, twenty-four million, one hundred forty-one thousand, two hundred ninety-one".
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