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131025241004112 = 24347313231127443
BaseRepresentation
bin11101110010101010110000…
…111100100101100001010000
3122011220220001022211120120000
4131302222300330211201100
5114133204143144112422
61142400055330450000
736412155421356000
oct3562526074454120
9564826038746500
10131025241004112
11388265467a90a4
12128416a0133900
13581581cc9a100
14244d9269a6000
151023401c3acac
hex772ab0f25850

131025241004112 has 2400 divisors, whose sum is σ = 499345411276800. Its totient is φ = 33103182228480.

The previous prime is 131025241004101. The next prime is 131025241004123. The reversal of 131025241004112 is 211400142520131.

131025241004112 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 2 + 5 + 241 + 0 + 0 + 411 + 2 = 666.

It is an interprime number because it is at equal distance from previous prime (131025241004101) and next prime (131025241004123).

It is a super-2 number, since 2×1310252410041122 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 479 ways as a sum of consecutive naturals, for example, 295768038163 + ... + 295768038605.

It is an arithmetic number, because the mean of its divisors is an integer number (208060588032).

Almost surely, 2131025241004112 is an apocalyptic number.

131025241004112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131025241004112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (249672705638400).

131025241004112 is an abundant number, since it is smaller than the sum of its proper divisors (368320170272688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131025241004112 is a wasteful number, since it uses less digits than its factorization.

131025241004112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668 (or 626 counting only the distinct ones).

The product of its (nonzero) digits is 1920, while the sum is 27.

Adding to 131025241004112 its reverse (211400142520131), we get a palindrome (342425383524243).

The spelling of 131025241004112 in words is "one hundred thirty-one trillion, twenty-five billion, two hundred forty-one million, four thousand, one hundred twelve".