Base | Representation |
---|---|
bin | 111101000000111010… |
… | …0011010100000111010 |
3 | 110112012111110020222110 |
4 | 1322001310122200322 |
5 | 4121320404113314 |
6 | 140105403433150 |
7 | 12315654202164 |
oct | 1720164324072 |
9 | 415174406873 |
10 | 131027019834 |
11 | 50628378357 |
12 | 214888257b6 |
13 | c4818b2389 |
14 | 64ada4b934 |
15 | 361d0d0a59 |
hex | 1e81d1a83a |
131027019834 has 32 divisors (see below), whose sum is σ = 266029868160. Its totient is φ = 43016855552.
The previous prime is 131027019833. The next prime is 131027019883. The reversal of 131027019834 is 438910720131.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 131027019792 and 131027019801.
It is not an unprimeable number, because it can be changed into a prime (131027019833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 340134 + ... + 614609.
It is an arithmetic number, because the mean of its divisors is an integer number (8313433380).
Almost surely, 2131027019834 is an apocalyptic number.
131027019834 is an abundant number, since it is smaller than the sum of its proper divisors (135002848326).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131027019834 is a wasteful number, since it uses less digits than its factorization.
131027019834 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 955094.
The product of its (nonzero) digits is 36288, while the sum is 39.
Adding to 131027019834 its reverse (438910720131), we get a palindrome (569937739965).
The spelling of 131027019834 in words is "one hundred thirty-one billion, twenty-seven million, nineteen thousand, eight hundred thirty-four".
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