Base | Representation |
---|---|
bin | 10011000100010011111… |
… | …101011100010011111011 |
3 | 11122021010001102112121202 |
4 | 103010103331130103323 |
5 | 132431443233233011 |
6 | 2441535442124415 |
7 | 163444311242666 |
oct | 23042375342373 |
9 | 4567101375552 |
10 | 1310299899131 |
11 | 465771151923 |
12 | 191b4095070b |
13 | 96739c78802 |
14 | 475c14966dd |
15 | 2413d2c223b |
hex | 13113f5c4fb |
1310299899131 has 2 divisors, whose sum is σ = 1310299899132. Its totient is φ = 1310299899130.
The previous prime is 1310299899127. The next prime is 1310299899149. The reversal of 1310299899131 is 1319989920131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310299899131 - 22 = 1310299899127 is a prime.
It is a super-2 number, since 2×13102998991312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310299829131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655149949565 + 655149949566.
It is an arithmetic number, because the mean of its divisors is an integer number (655149949566).
Almost surely, 21310299899131 is an apocalyptic number.
1310299899131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310299899131 is an equidigital number, since it uses as much as digits as its factorization.
1310299899131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 944784, while the sum is 56.
The spelling of 1310299899131 in words is "one trillion, three hundred ten billion, two hundred ninety-nine million, eight hundred ninety-nine thousand, one hundred thirty-one".
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