Base | Representation |
---|---|
bin | 111101000000111111… |
… | …1110101000011100011 |
3 | 110112012201002021122021 |
4 | 1322001333311003203 |
5 | 4121322140342011 |
6 | 140105551522311 |
7 | 12316021504114 |
oct | 1720177650343 |
9 | 415181067567 |
10 | 131030012131 |
11 | 5062a031527 |
12 | 21489829397 |
13 | c4823bc375 |
14 | 64b01ca20b |
15 | 361d4c2471 |
hex | 1e81ff50e3 |
131030012131 has 2 divisors, whose sum is σ = 131030012132. Its totient is φ = 131030012130.
The previous prime is 131030012101. The next prime is 131030012177. The reversal of 131030012131 is 131210030131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131030012131 - 215 = 131029979363 is a prime.
It is a super-2 number, since 2×1310300121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131030012101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515006065 + 65515006066.
It is an arithmetic number, because the mean of its divisors is an integer number (65515006066).
Almost surely, 2131030012131 is an apocalyptic number.
131030012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030012131 is an equidigital number, since it uses as much as digits as its factorization.
131030012131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131030012131 its reverse (131210030131), we get a palindrome (262240042262).
The spelling of 131030012131 in words is "one hundred thirty-one billion, thirty million, twelve thousand, one hundred thirty-one".
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