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1310300131200 = 273521959313389
BaseRepresentation
bin10011000100010011111…
…110010100111110000000
311122021010001212022221220
4103010103332110332000
5132431443313144300
62441535451115040
7163444313230404
oct23042376247600
94567101768856
101310300131200
114657712a0215
12191b40a42a80
139673a02a328
14475c1517104
152413d31ada0
hex13113f94f80

1310300131200 has 768 divisors, whose sum is σ = 4646622240000. Its totient is φ = 323539107840.

The previous prime is 1310300131187. The next prime is 1310300131237. The reversal of 1310300131200 is 21310030131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1310300131200.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3368380606 + ... + 3368380994.

It is an arithmetic number, because the mean of its divisors is an integer number (6050289375).

Almost surely, 21310300131200 is an apocalyptic number.

1310300131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1310300131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2323311120000).

1310300131200 is an abundant number, since it is smaller than the sum of its proper divisors (3336322108800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310300131200 is a wasteful number, since it uses less digits than its factorization.

1310300131200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 807 (or 790 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1310300131200 its reverse (21310030131), we get a palindrome (1331610161331).

The spelling of 1310300131200 in words is "one trillion, three hundred ten billion, three hundred million, one hundred thirty-one thousand, two hundred".