13103011011331 has 2 divisors, whose sum is σ = 13103011011332. Its totient is φ = 13103011011330.

The previous prime is 13103011011271. The next prime is 13103011011341. The reversal of 13103011011331 is 13311011030131.

It is a strong prime.

It is an emirp because it is prime and its reverse (13311011030131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13103011011331 - 2³³ = 13094421076739 is a prime.

It is a super-3 number, since 3×13103011011331³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13103011011299 and 13103011011308.

It is not a weakly prime, because it can be changed into another prime (13103011011341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551505505665 + 6551505505666.

It is an arithmetic number, because the mean of its divisors is an integer number (6551505505666).

Almost surely, 2^{13103011011331} is an apocalyptic number.

13103011011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103011011331 is an equidigital number, since it uses as much as digits as its factorization.

13103011011331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 13103011011331 its reverse (13311011030131), we get a palindrome (26414022041462).

The spelling of 13103011011331 in words is "thirteen trillion, one hundred three billion, eleven million, eleven thousand, three hundred thirty-one".