13103011147 has 2 divisors, whose sum is σ = 13103011148. Its totient is φ = 13103011146.

The previous prime is 13103011093. The next prime is 13103011247. The reversal of 13103011147 is 74111030131.

It is a weak prime.

It is an emirp because it is prime and its reverse (74111030131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13103011147 is a prime.

It is a super-2 number, since 2×13103011147² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13103011247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551505573 + 6551505574.

It is an arithmetic number, because the mean of its divisors is an integer number (6551505574).

Almost surely, 2^13103011147 is an apocalyptic number.

13103011147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103011147 is an equidigital number, since it uses as much as digits as its factorization.

13103011147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 13103011147 its reverse (74111030131), we get a palindrome (87214041278).

The spelling of 13103011147 in words is "thirteen billion, one hundred three million, eleven thousand, one hundred forty-seven".