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13103011221301 = 53569434493193
BaseRepresentation
bin1011111010101100100001…
…0101000100111100110101
31201101122011101021202121001
42332223020111010330311
53204134431333040201
643511235032323301
72521442555466631
oct276531025047465
951348141252531
1013103011221301
1141a1a5726aa41
12157754bb43531
137407bb2aaac1
14334290d6ddc1
1517ac8ce30301
hexbeac8544f35

13103011221301 has 8 divisors (see below), whose sum is σ = 13373700511320. Its totient is φ = 12833190918912.

The previous prime is 13103011221163. The next prime is 13103011221319. The reversal of 13103011221301 is 10312211030131.

It can be written as a sum of positive squares in 4 ways, for example, as 2336908403025 + 10766102818276 = 1528695^2 + 3281174^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13103011221301 is a prime.

It is a super-2 number, since 2×131030112213012 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103011221341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 217216440 + ... + 217276753.

It is an arithmetic number, because the mean of its divisors is an integer number (1671712563915).

Almost surely, 213103011221301 is an apocalyptic number.

It is an amenable number.

13103011221301 is a deficient number, since it is larger than the sum of its proper divisors (270689290019).

13103011221301 is an equidigital number, since it uses as much as digits as its factorization.

13103011221301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434493815.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13103011221301 its reverse (10312211030131), we get a palindrome (23415222251432).

The spelling of 13103011221301 in words is "thirteen trillion, one hundred three billion, eleven million, two hundred twenty-one thousand, three hundred one".

Divisors: 1 53 569 30157 434493193 23028139229 247226626817 13103011221301