Base | Representation |
---|---|
bin | 11101110010101111011001… |
… | …110110000000110011010011 |
3 | 122011221100220110200011202112 |
4 | 131302233121312000303103 |
5 | 114133244343330122003 |
6 | 1142402241505135535 |
7 | 36412423024166162 |
oct | 3562573166006323 |
9 | 564840813604675 |
10 | 131030222114003 |
11 | 38828672483743 |
12 | 1284265032a5ab |
13 | 5816134c43804 |
14 | 244dc7a34b3d9 |
15 | 10235e41b03d8 |
hex | 772bd9d80cd3 |
131030222114003 has 2 divisors, whose sum is σ = 131030222114004. Its totient is φ = 131030222114002.
The previous prime is 131030222113979. The next prime is 131030222114087. The reversal of 131030222114003 is 300411222030131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131030222114003 - 212 = 131030222109907 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131030222114003.
It is not a weakly prime, because it can be changed into another prime (131030222119003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515111057001 + 65515111057002.
It is an arithmetic number, because the mean of its divisors is an integer number (65515111057002).
Almost surely, 2131030222114003 is an apocalyptic number.
131030222114003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030222114003 is an equidigital number, since it uses as much as digits as its factorization.
131030222114003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131030222114003 its reverse (300411222030131), we get a palindrome (431441444144134).
The spelling of 131030222114003 in words is "one hundred thirty-one trillion, thirty billion, two hundred twenty-two million, one hundred fourteen thousand, three".
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