Base | Representation |
---|---|
bin | 111101000001000000… |
… | …1010100000011100011 |
3 | 110112012201211001102010 |
4 | 1322002001110003203 |
5 | 4121322240320001 |
6 | 140110004124003 |
7 | 12316025014431 |
oct | 1720201240343 |
9 | 415181731363 |
10 | 131030401251 |
11 | 5062a277912 |
12 | 21489996603 |
13 | c4824c7509 |
14 | 64b028bd51 |
15 | 361d54c8d6 |
hex | 1e820540e3 |
131030401251 has 32 divisors (see below), whose sum is σ = 176984349696. Its totient is φ = 86224320000.
The previous prime is 131030401193. The next prime is 131030401253. The reversal of 131030401251 is 152104030131.
It is not a de Polignac number, because 131030401251 - 213 = 131030393059 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131030401253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55732726 + ... + 55735076.
It is an arithmetic number, because the mean of its divisors is an integer number (5530760928).
Almost surely, 2131030401251 is an apocalyptic number.
131030401251 is a deficient number, since it is larger than the sum of its proper divisors (45953948445).
131030401251 is a wasteful number, since it uses less digits than its factorization.
131030401251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3243.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 131030401251 its reverse (152104030131), we get a palindrome (283134431382).
The spelling of 131030401251 in words is "one hundred thirty-one billion, thirty million, four hundred one thousand, two hundred fifty-one".
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