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131030401253 is a prime number
BaseRepresentation
bin111101000001000000…
…1010100000011100101
3110112012201211001102012
41322002001110003211
54121322240320003
6140110004124005
712316025014433
oct1720201240345
9415181731365
10131030401253
115062a277914
1221489996605
13c4824c750b
1464b028bd53
15361d54c8d8
hex1e820540e5

131030401253 has 2 divisors, whose sum is σ = 131030401254. Its totient is φ = 131030401252.

The previous prime is 131030401193. The next prime is 131030401267. The reversal of 131030401253 is 352104030131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92356425604 + 38673975649 = 303902^2 + 196657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131030401253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131030401283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515200626 + 65515200627.

It is an arithmetic number, because the mean of its divisors is an integer number (65515200627).

Almost surely, 2131030401253 is an apocalyptic number.

It is an amenable number.

131030401253 is a deficient number, since it is larger than the sum of its proper divisors (1).

131030401253 is an equidigital number, since it uses as much as digits as its factorization.

131030401253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 131030401253 its reverse (352104030131), we get a palindrome (483134431384).

The spelling of 131030401253 in words is "one hundred thirty-one billion, thirty million, four hundred one thousand, two hundred fifty-three".