Base | Representation |
---|---|
bin | 111101000001000000… |
… | …1010100000011100101 |
3 | 110112012201211001102012 |
4 | 1322002001110003211 |
5 | 4121322240320003 |
6 | 140110004124005 |
7 | 12316025014433 |
oct | 1720201240345 |
9 | 415181731365 |
10 | 131030401253 |
11 | 5062a277914 |
12 | 21489996605 |
13 | c4824c750b |
14 | 64b028bd53 |
15 | 361d54c8d8 |
hex | 1e820540e5 |
131030401253 has 2 divisors, whose sum is σ = 131030401254. Its totient is φ = 131030401252.
The previous prime is 131030401193. The next prime is 131030401267. The reversal of 131030401253 is 352104030131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92356425604 + 38673975649 = 303902^2 + 196657^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131030401253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131030401283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515200626 + 65515200627.
It is an arithmetic number, because the mean of its divisors is an integer number (65515200627).
Almost surely, 2131030401253 is an apocalyptic number.
It is an amenable number.
131030401253 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030401253 is an equidigital number, since it uses as much as digits as its factorization.
131030401253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 131030401253 its reverse (352104030131), we get a palindrome (483134431384).
The spelling of 131030401253 in words is "one hundred thirty-one billion, thirty million, four hundred one thousand, two hundred fifty-three".
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