Base | Representation |
---|---|
bin | 11000011010000000… |
… | …10011001111111001 |
3 | 1020211011202122212022 |
4 | 30031000103033321 |
5 | 203313342201122 |
6 | 10004112324225 |
7 | 642464244434 |
oct | 141500231771 |
9 | 36734678768 |
10 | 13103084537 |
11 | 5614393394 |
12 | 2658243675 |
13 | 130a85547a |
14 | 8c432081b |
15 | 51a515642 |
hex | 30d0133f9 |
13103084537 has 2 divisors, whose sum is σ = 13103084538. Its totient is φ = 13103084536.
The previous prime is 13103084497. The next prime is 13103084563. The reversal of 13103084537 is 73548030131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12549376576 + 553707961 = 112024^2 + 23531^2 .
It is a cyclic number.
It is not a de Polignac number, because 13103084537 - 218 = 13102822393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13103084497 and 13103084506.
It is not a weakly prime, because it can be changed into another prime (13103086537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551542268 + 6551542269.
It is an arithmetic number, because the mean of its divisors is an integer number (6551542269).
Almost surely, 213103084537 is an apocalyptic number.
It is an amenable number.
13103084537 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103084537 is an equidigital number, since it uses as much as digits as its factorization.
13103084537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 35.
The spelling of 13103084537 in words is "thirteen billion, one hundred three million, eighty-four thousand, five hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •