Base | Representation |
---|---|
bin | 11101110010110000000000… |
… | …111000001001100010000001 |
3 | 122011221102121002221002112102 |
4 | 131302300000320021202001 |
5 | 114133302214002013343 |
6 | 1142402430501240145 |
7 | 36412445165412353 |
oct | 3562600070114201 |
9 | 564842532832472 |
10 | 131030876985473 |
11 | 388289790aa333 |
12 | 128427b3703055 |
13 | 581620a811c1a |
14 | 244dcdd2d90d3 |
15 | 102363191b3b8 |
hex | 772c00e09881 |
131030876985473 has 2 divisors, whose sum is σ = 131030876985474. Its totient is φ = 131030876985472.
The previous prime is 131030876985469. The next prime is 131030876985479. The reversal of 131030876985473 is 374589678030131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111774647956609 + 19256229028864 = 10572353^2 + 4388192^2 .
It is a cyclic number.
It is not a de Polignac number, because 131030876985473 - 22 = 131030876985469 is a prime.
It is not a weakly prime, because it can be changed into another prime (131030876985479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515438492736 + 65515438492737.
It is an arithmetic number, because the mean of its divisors is an integer number (65515438492737).
Almost surely, 2131030876985473 is an apocalyptic number.
It is an amenable number.
131030876985473 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030876985473 is an equidigital number, since it uses as much as digits as its factorization.
131030876985473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 91445760, while the sum is 65.
The spelling of 131030876985473 in words is "one hundred thirty-one trillion, thirty billion, eight hundred seventy-six million, nine hundred eighty-five thousand, four hundred seventy-three".
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