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13103104111020 = 223557211217231163
BaseRepresentation
bin1011111010101100110111…
…0111011011000110101100
31201101122101212002001100000
42332223031313123012230
53204140124123023040
643511252151304300
72521445064156300
oct276531567330654
951348355061300
1013103104111020
1141a1aa4745400
12157757707b090
13740804602131
1433429d42dd00
1517ac9617d130
hexbeacdddb1ac

13103104111020 has 2592 divisors, whose sum is σ = 58279242438144. Its totient is φ = 2449039380480.

The previous prime is 13103104111001. The next prime is 13103104111021. The reversal of 13103104111020 is 2011140130131.

It is a happy number.

13103104111020 is a `hidden beast` number, since 1 + 310 + 310 + 4 + 11 + 10 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13103104110984 and 13103104111002.

It is not an unprimeable number, because it can be changed into a prime (13103104111021) by changing a digit.

It is a polite number, since it can be written in 863 ways as a sum of consecutive naturals, for example, 11266640959 + ... + 11266642121.

It is an arithmetic number, because the mean of its divisors is an integer number (22484275632).

Almost surely, 213103104111020 is an apocalyptic number.

13103104111020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13103104111020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29139621219072).

13103104111020 is an abundant number, since it is smaller than the sum of its proper divisors (45176138327124).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103104111020 is a wasteful number, since it uses less digits than its factorization.

13103104111020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1263 (or 1231 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13103104111020 its reverse (2011140130131), we get a palindrome (15114244241151).

The spelling of 13103104111020 in words is "thirteen trillion, one hundred three billion, one hundred four million, one hundred eleven thousand, twenty".