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13103121311002 = 26551560655501
BaseRepresentation
bin1011111010101100111011…
…1001000010010100011010
31201101122110001102220021101
42332223032321002110122
53204140143023423002
643511254004102014
72521445363314102
oct276531671022432
951348401386241
1013103121311002
1141a2003422a68
12157758099490a
13740808044c38
143342a182a202
1517ac97929587
hexbeacee4251a

13103121311002 has 4 divisors (see below), whose sum is σ = 19654681966506. Its totient is φ = 6551560655500.

The previous prime is 13103121310963. The next prime is 13103121311009. The reversal of 13103121311002 is 20011312130131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10337954742361 + 2765166568641 = 3215269^2 + 1662879^2 .

It is not an unprimeable number, because it can be changed into a prime (13103121311009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275780327749 + ... + 3275780327752.

Almost surely, 213103121311002 is an apocalyptic number.

13103121311002 is a deficient number, since it is larger than the sum of its proper divisors (6551560655504).

13103121311002 is an equidigital number, since it uses as much as digits as its factorization.

13103121311002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6551560655503.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13103121311002 its reverse (20011312130131), we get a palindrome (33114433441133).

The spelling of 13103121311002 in words is "thirteen trillion, one hundred three billion, one hundred twenty-one million, three hundred eleven thousand, two".

Divisors: 1 2 6551560655501 13103121311002