Base | Representation |
---|---|
bin | 1011111010101100111011… |
… | …1001000010010100011010 |
3 | 1201101122110001102220021101 |
4 | 2332223032321002110122 |
5 | 3204140143023423002 |
6 | 43511254004102014 |
7 | 2521445363314102 |
oct | 276531671022432 |
9 | 51348401386241 |
10 | 13103121311002 |
11 | 41a2003422a68 |
12 | 157758099490a |
13 | 740808044c38 |
14 | 3342a182a202 |
15 | 17ac97929587 |
hex | beacee4251a |
13103121311002 has 4 divisors (see below), whose sum is σ = 19654681966506. Its totient is φ = 6551560655500.
The previous prime is 13103121310963. The next prime is 13103121311009. The reversal of 13103121311002 is 20011312130131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10337954742361 + 2765166568641 = 3215269^2 + 1662879^2 .
It is not an unprimeable number, because it can be changed into a prime (13103121311009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275780327749 + ... + 3275780327752.
Almost surely, 213103121311002 is an apocalyptic number.
13103121311002 is a deficient number, since it is larger than the sum of its proper divisors (6551560655504).
13103121311002 is an equidigital number, since it uses as much as digits as its factorization.
13103121311002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6551560655503.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13103121311002 its reverse (20011312130131), we get a palindrome (33114433441133).
The spelling of 13103121311002 in words is "thirteen trillion, one hundred three billion, one hundred twenty-one million, three hundred eleven thousand, two".
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