Base | Representation |
---|---|
bin | 1011111010101100111011… |
… | …1001000010010011110011 |
3 | 1201101122110001102220012221 |
4 | 2332223032321002103303 |
5 | 3204140143023422323 |
6 | 43511254004101511 |
7 | 2521445363314015 |
oct | 276531671022363 |
9 | 51348401386187 |
10 | 13103121310963 |
11 | 41a2003422a32 |
12 | 1577580994897 |
13 | 740808044c08 |
14 | 3342a182a1b5 |
15 | 17ac9792955d |
hex | beacee424f3 |
13103121310963 has 2 divisors, whose sum is σ = 13103121310964. Its totient is φ = 13103121310962.
The previous prime is 13103121310943. The next prime is 13103121311009. The reversal of 13103121310963 is 36901312130131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13103121310963 - 217 = 13103121179891 is a prime.
It is a super-4 number, since 4×131031213109634 (a number of 54 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (13103121310943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551560655481 + 6551560655482.
It is an arithmetic number, because the mean of its divisors is an integer number (6551560655482).
Almost surely, 213103121310963 is an apocalyptic number.
13103121310963 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103121310963 is an equidigital number, since it uses as much as digits as its factorization.
13103121310963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8748, while the sum is 34.
The spelling of 13103121310963 in words is "thirteen trillion, one hundred three billion, one hundred twenty-one million, three hundred ten thousand, nine hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •