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131031314144329 is a prime number
BaseRepresentation
bin11101110010110000011010…
…111011110001110001001001
3122011221110201120112001202011
4131302300122323301301021
5114133304112410104304
61142402542115135521
736412462054250104
oct3562603273616111
9564843646461664
10131031314144329
1138829082945245
12128428b5ba45a1
13581627a263ac1
14244dd413b373b
151023659ebec04
hex772c1aef1c49

131031314144329 has 2 divisors, whose sum is σ = 131031314144330. Its totient is φ = 131031314144328.

The previous prime is 131031314144287. The next prime is 131031314144333. The reversal of 131031314144329 is 923441413130131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126203362636729 + 4827951507600 = 11234027^2 + 2197260^2 .

It is a cyclic number.

It is not a de Polignac number, because 131031314144329 - 213 = 131031314136137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131031314144291 and 131031314144300.

It is not a weakly prime, because it can be changed into another prime (131031314544329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515657072164 + 65515657072165.

It is an arithmetic number, because the mean of its divisors is an integer number (65515657072165).

Almost surely, 2131031314144329 is an apocalyptic number.

It is an amenable number.

131031314144329 is a deficient number, since it is larger than the sum of its proper divisors (1).

131031314144329 is an equidigital number, since it uses as much as digits as its factorization.

131031314144329 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 40.

The spelling of 131031314144329 in words is "one hundred thirty-one trillion, thirty-one billion, three hundred fourteen million, one hundred forty-four thousand, three hundred twenty-nine".