Base | Representation |
---|---|
bin | 1011111010101101000010… |
… | …1000111000010010001001 |
3 | 1201101122112002121110102010 |
4 | 2332223100220320102021 |
5 | 3204140223030130100 |
6 | 43511300532330133 |
7 | 2521446200445231 |
oct | 276532050702211 |
9 | 51348462543363 |
10 | 13103150630025 |
11 | 41a2018a28865 |
12 | 157758a773949 |
13 | 74081113bc81 |
14 | 3342a569ccc1 |
15 | 17ac9a2bb750 |
hex | bead0a38489 |
13103150630025 has 12 divisors (see below), whose sum is σ = 21663875708432. Its totient is φ = 6988347002640.
The previous prime is 13103150630023. The next prime is 13103150630069. The reversal of 13103150630025 is 52003605130131.
It is not a de Polignac number, because 13103150630025 - 21 = 13103150630023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13103150629974 and 13103150630001.
It is not an unprimeable number, because it can be changed into a prime (13103150630023) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87354337459 + ... + 87354337608.
Almost surely, 213103150630025 is an apocalyptic number.
13103150630025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13103150630025 is a deficient number, since it is larger than the sum of its proper divisors (8560725078407).
13103150630025 is a wasteful number, since it uses less digits than its factorization.
13103150630025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174708675080 (or 174708675075 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 13103150630025 its reverse (52003605130131), we get a palindrome (65106755760156).
The spelling of 13103150630025 in words is "thirteen trillion, one hundred three billion, one hundred fifty million, six hundred thirty thousand, twenty-five".
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