Base | Representation |
---|---|
bin | 1011111010101101010001… |
… | …0000010100110010101011 |
3 | 1201101122200022202220210111 |
4 | 2332223110100110302223 |
5 | 3204140334043131214 |
6 | 43511310540555151 |
7 | 2521450535241514 |
oct | 276532420246253 |
9 | 51348608686714 |
10 | 13103211302059 |
11 | 41a204a1a863a |
12 | 15775a6b52ab7 |
13 | 740820892a98 |
14 | 3342ad773a0b |
15 | 17aca07a35c4 |
hex | bead4414cab |
13103211302059 has 2 divisors, whose sum is σ = 13103211302060. Its totient is φ = 13103211302058.
The previous prime is 13103211302017. The next prime is 13103211302063. The reversal of 13103211302059 is 95020311230131.
13103211302059 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13103211302059 - 27 = 13103211301931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13103211302059.
It is not a weakly prime, because it can be changed into another prime (13103211302459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551605651029 + 6551605651030.
It is an arithmetic number, because the mean of its divisors is an integer number (6551605651030).
Almost surely, 213103211302059 is an apocalyptic number.
13103211302059 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103211302059 is an equidigital number, since it uses as much as digits as its factorization.
13103211302059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 13103211302059 in words is "thirteen trillion, one hundred three billion, two hundred eleven million, three hundred two thousand, fifty-nine".
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