Base | Representation |
---|---|
bin | 10011000100010101001… |
… | …110101111101101010001 |
3 | 11122021011112112100201012 |
4 | 103010111032233231101 |
5 | 132432014212242431 |
6 | 2441541523020305 |
7 | 163444660351226 |
oct | 23042516575521 |
9 | 4567145470635 |
10 | 1310321212241 |
11 | 465782189768 |
12 | 191b47b0a695 |
13 | 967414cb812 |
14 | 475c424394d |
15 | 241400d222b |
hex | 131153afb51 |
1310321212241 has 2 divisors, whose sum is σ = 1310321212242. Its totient is φ = 1310321212240.
The previous prime is 1310321212217. The next prime is 1310321212267. The reversal of 1310321212241 is 1422121230131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1206043240000 + 104277972241 = 1098200^2 + 322921^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310321212241 - 214 = 1310321195857 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310321212141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655160606120 + 655160606121.
It is an arithmetic number, because the mean of its divisors is an integer number (655160606121).
Almost surely, 21310321212241 is an apocalyptic number.
It is an amenable number.
1310321212241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310321212241 is an equidigital number, since it uses as much as digits as its factorization.
1310321212241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1310321212241 its reverse (1422121230131), we get a palindrome (2732442442372).
The spelling of 1310321212241 in words is "one trillion, three hundred ten billion, three hundred twenty-one million, two hundred twelve thousand, two hundred forty-one".
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