Base | Representation |
---|---|
bin | 1011111010101101010110… |
… | …0011100011111100110111 |
3 | 1201101122201211211111021021 |
4 | 2332223111203203330313 |
5 | 3204140410134401403 |
6 | 43511313040402011 |
7 | 2521451221561015 |
oct | 276532543437467 |
9 | 51348654744237 |
10 | 13103233122103 |
11 | 41a2060551333 |
12 | 15775b2316307 |
13 | 740825262757 |
14 | 3342b26138b5 |
15 | 17aca26638bd |
hex | bead58e3f37 |
13103233122103 has 4 divisors (see below), whose sum is σ = 13144568242680. Its totient is φ = 13061898001528.
The previous prime is 13103233122061. The next prime is 13103233122173. The reversal of 13103233122103 is 30122133230131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13103233122103 - 217 = 13103232991031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103233122173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20667559813 + ... + 20667560446.
It is an arithmetic number, because the mean of its divisors is an integer number (3286142060670).
Almost surely, 213103233122103 is an apocalyptic number.
13103233122103 is a deficient number, since it is larger than the sum of its proper divisors (41335120577).
13103233122103 is an equidigital number, since it uses as much as digits as its factorization.
13103233122103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41335120576.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13103233122103 its reverse (30122133230131), we get a palindrome (43225366352234).
The spelling of 13103233122103 in words is "thirteen trillion, one hundred three billion, two hundred thirty-three million, one hundred twenty-two thousand, one hundred three".
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