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131032424009 is a prime number
BaseRepresentation
bin111101000001000100…
…1000001111001001001
3110112012212121211010002
41322002021001321021
54121323300032014
6140110115332345
712316051140614
oct1720211017111
9415185554102
10131032424009
1150630429613
122148a5b10b5
13c482a55106
1464b065717b
15361d7ebdde
hex1e82241e49

131032424009 has 2 divisors, whose sum is σ = 131032424010. Its totient is φ = 131032424008.

The previous prime is 131032423981. The next prime is 131032424057. The reversal of 131032424009 is 900424230131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118201878025 + 12830545984 = 343805^2 + 113272^2 .

It is an emirp because it is prime and its reverse (900424230131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131032424009 - 224 = 131015646793 is a prime.

It is a super-2 number, since 2×1310324240092 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131032424069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516212004 + 65516212005.

It is an arithmetic number, because the mean of its divisors is an integer number (65516212005).

Almost surely, 2131032424009 is an apocalyptic number.

It is an amenable number.

131032424009 is a deficient number, since it is larger than the sum of its proper divisors (1).

131032424009 is an equidigital number, since it uses as much as digits as its factorization.

131032424009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The spelling of 131032424009 in words is "one hundred thirty-one billion, thirty-two million, four hundred twenty-four thousand, nine".