Base | Representation |
---|---|
bin | 1011111010101101100110… |
… | …0111010101101101100111 |
3 | 1201101122220120222021200220 |
4 | 2332223121213111231213 |
5 | 3204141030103034343 |
6 | 43511323512135423 |
7 | 2521453006446513 |
oct | 276533147255547 |
9 | 51348816867626 |
10 | 13103301221223 |
11 | 41a2095a341a4 |
12 | 1577611097573 |
13 | 7408363b6ca5 |
14 | 3342bb69d143 |
15 | 17aca8616183 |
hex | bead99d5b67 |
13103301221223 has 4 divisors (see below), whose sum is σ = 17471068294968. Its totient is φ = 8735534147480.
The previous prime is 13103301221203. The next prime is 13103301221237. The reversal of 13103301221223 is 32212210330131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13103301221223 - 225 = 13103267666791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13103301221193 and 13103301221202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103301221203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183883536868 + ... + 2183883536873.
It is an arithmetic number, because the mean of its divisors is an integer number (4367767073742).
Almost surely, 213103301221223 is an apocalyptic number.
13103301221223 is a deficient number, since it is larger than the sum of its proper divisors (4367767073745).
13103301221223 is an equidigital number, since it uses as much as digits as its factorization.
13103301221223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4367767073744.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13103301221223 its reverse (32212210330131), we get a palindrome (45315511551354).
The spelling of 13103301221223 in words is "thirteen trillion, one hundred three billion, three hundred one million, two hundred twenty-one thousand, two hundred twenty-three".
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