Base | Representation |
---|---|
bin | 10011000100010110101… |
… | …001100000000000011011 |
3 | 11122021020012022001112201 |
4 | 103010112221200000123 |
5 | 132432041310044120 |
6 | 2441544132551031 |
7 | 163445366516155 |
oct | 23042651400033 |
9 | 4567205261481 |
10 | 1310345003035 |
11 | 465794659082 |
12 | 191b53a82477 |
13 | 9674640b503 |
14 | 475c7477ad5 |
15 | 2414223140a |
hex | 13116a6001b |
1310345003035 has 24 divisors (see below), whose sum is σ = 1602174485520. Its totient is φ = 1028786577984.
The previous prime is 1310345002999. The next prime is 1310345003039. The reversal of 1310345003035 is 5303005430131.
It is a de Polignac number, because none of the positive numbers 2k-1310345003035 is a prime.
It is a super-2 number, since 2×13103450030352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310345002994 and 1310345003012.
It is not an unprimeable number, because it can be changed into a prime (1310345003039) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5929192 + ... + 6146218.
It is an arithmetic number, because the mean of its divisors is an integer number (66757270230).
Almost surely, 21310345003035 is an apocalyptic number.
1310345003035 is a deficient number, since it is larger than the sum of its proper divisors (291829482485).
1310345003035 is an equidigital number, since it uses as much as digits as its factorization.
1310345003035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 217435 (or 217368 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 28.
The spelling of 1310345003035 in words is "one trillion, three hundred ten billion, three hundred forty-five million, three thousand, thirty-five".
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