Base | Representation |
---|---|
bin | 111101000001001000… |
… | …1000110110100001001 |
3 | 110112020000121101112001 |
4 | 1322002101012310021 |
5 | 4121324320310241 |
6 | 140110232551001 |
7 | 12316105136545 |
oct | 1720221066411 |
9 | 415200541461 |
10 | 131034541321 |
11 | 50631645362 |
12 | 2148b252461 |
13 | c483316a68 |
14 | 64b0a48a25 |
15 | 361dab9431 |
hex | 1e82446d09 |
131034541321 has 2 divisors, whose sum is σ = 131034541322. Its totient is φ = 131034541320.
The previous prime is 131034541289. The next prime is 131034541327. The reversal of 131034541321 is 123145430131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 121574255625 + 9460285696 = 348675^2 + 97264^2 .
It is a cyclic number.
It is not a de Polignac number, because 131034541321 - 25 = 131034541289 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131034541321.
It is not a weakly prime, because it can be changed into another prime (131034541327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65517270660 + 65517270661.
It is an arithmetic number, because the mean of its divisors is an integer number (65517270661).
Almost surely, 2131034541321 is an apocalyptic number.
It is an amenable number.
131034541321 is a deficient number, since it is larger than the sum of its proper divisors (1).
131034541321 is an equidigital number, since it uses as much as digits as its factorization.
131034541321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 131034541321 its reverse (123145430131), we get a palindrome (254179971452).
The spelling of 131034541321 in words is "one hundred thirty-one billion, thirty-four million, five hundred forty-one thousand, three hundred twenty-one".
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