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131035535032433 is a prime number
BaseRepresentation
bin11101110010110100010110…
…100001001100000001110001
3122011221212121201212101201012
4131302310112201030001301
5114133341233432014213
61142404521015320305
736413001466226243
oct3562642641140161
9564855551771635
10131035535032433
113882a949488a19
1212843693680095
1358167a0874225
142450221bc6093
1510238058284a8
hex772d1684c071

131035535032433 has 2 divisors, whose sum is σ = 131035535032434. Its totient is φ = 131035535032432.

The previous prime is 131035535032421. The next prime is 131035535032447. The reversal of 131035535032433 is 334230535530131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114345638335504 + 16689896696929 = 10693252^2 + 4085327^2 .

It is a cyclic number.

It is not a de Polignac number, because 131035535032433 - 240 = 129936023404657 is a prime.

It is a super-2 number, since 2×1310355350324332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131035535032333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65517767516216 + 65517767516217.

It is an arithmetic number, because the mean of its divisors is an integer number (65517767516217).

Almost surely, 2131035535032433 is an apocalyptic number.

It is an amenable number.

131035535032433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131035535032433 is an equidigital number, since it uses as much as digits as its factorization.

131035535032433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 729000, while the sum is 41.

The spelling of 131035535032433 in words is "one hundred thirty-one trillion, thirty-five billion, five hundred thirty-five million, thirty-two thousand, four hundred thirty-three".