131040113404200 has 768 divisors, whose sum is σ = 560161287383040. Its totient is φ = 24455250432000.

The previous prime is 131040113404177. The next prime is 131040113404261. The reversal of 131040113404200 is 2404311040131.

It is a super-2 number, since 2×131040113404200² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 19273795 + ... + 25170605.

It is an arithmetic number, because the mean of its divisors is an integer number (729376676280).

Almost surely, 2^{131040113404200} is an apocalyptic number.

131040113404200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131040113404200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (280080643691520).

131040113404200 is an abundant number, since it is smaller than the sum of its proper divisors (429121173978840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131040113404200 is a wasteful number, since it uses less digits than its factorization.

131040113404200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5896898 (or 5896889 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131040113404200 its reverse (2404311040131), we get a palindrome (133444424444331).

The spelling of 131040113404200 in words is "one hundred thirty-one trillion, forty billion, one hundred thirteen million, four hundred four thousand, two hundred".