Base | Representation |
---|---|
bin | 10011000100011010000… |
… | …111111110100011000111 |
3 | 11122021101021001002000021 |
4 | 103010122013332203013 |
5 | 132432201222332403 |
6 | 2441554015000011 |
7 | 163450005321346 |
oct | 23043207764307 |
9 | 4567337032007 |
10 | 1310403324103 |
11 | 465814572605 |
12 | 191b6b509007 |
13 | 9675551b213 |
14 | 475d10d9b5d |
15 | 241474018bd |
hex | 1311a1fe8c7 |
1310403324103 has 4 divisors (see below), whose sum is σ = 1312480033648. Its totient is φ = 1308326614560.
The previous prime is 1310403324067. The next prime is 1310403324149. The reversal of 1310403324103 is 3014233040131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310403324103 - 217 = 1310403193031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310403321103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1038353826 + ... + 1038355087.
It is an arithmetic number, because the mean of its divisors is an integer number (328120008412).
Almost surely, 21310403324103 is an apocalyptic number.
1310403324103 is a deficient number, since it is larger than the sum of its proper divisors (2076709545).
1310403324103 is an equidigital number, since it uses as much as digits as its factorization.
1310403324103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2076709544.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1310403324103 its reverse (3014233040131), we get a palindrome (4324636364234).
The spelling of 1310403324103 in words is "one trillion, three hundred ten billion, four hundred three million, three hundred twenty-four thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •