Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0001001110101011001110 |
3 | 1201101201211012220022200222 |
4 | 2332230011301032223032 |
5 | 3204144034223330332 |
6 | 43511525213551342 |
7 | 2521510243166462 |
oct | 276540561165316 |
9 | 51351735808628 |
10 | 13104042011342 |
11 | 41a2436103837 |
12 | 15777991a5552 |
13 | 740923a08739 |
14 | 33434bc144a2 |
15 | 17aced694712 |
hex | beb05c4eace |
13104042011342 has 4 divisors (see below), whose sum is σ = 19656063017016. Its totient is φ = 6552021005670.
The previous prime is 13104042011327. The next prime is 13104042011353. The reversal of 13104042011342 is 24311024040131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276010502834 + ... + 3276010502837.
It is an arithmetic number, because the mean of its divisors is an integer number (4914015754254).
Almost surely, 213104042011342 is an apocalyptic number.
13104042011342 is a deficient number, since it is larger than the sum of its proper divisors (6552021005674).
13104042011342 is an equidigital number, since it uses as much as digits as its factorization.
13104042011342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6552021005673.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 13104042011342 its reverse (24311024040131), we get a palindrome (37415066051473).
The spelling of 13104042011342 in words is "thirteen trillion, one hundred four billion, forty-two million, eleven thousand, three hundred forty-two".
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