Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0101110011010111011001 |
3 | 1201101201211022011020020011 |
4 | 2332230011311303113121 |
5 | 3204144040030211301 |
6 | 43511525255401521 |
7 | 2521510256321626 |
oct | 276540565632731 |
9 | 51351738136204 |
10 | 13104043210201 |
11 | 41a2436852529 |
12 | 15777996832a1 |
13 | 740924038318 |
14 | 33434c04734d |
15 | 17aced82ea51 |
hex | beb05d735d9 |
13104043210201 has 2 divisors, whose sum is σ = 13104043210202. Its totient is φ = 13104043210200.
The previous prime is 13104043210147. The next prime is 13104043210241. The reversal of 13104043210201 is 10201234040131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7605041660176 + 5499001550025 = 2757724^2 + 2344995^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104043210201 - 241 = 10905019954649 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104043210241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552021605100 + 6552021605101.
It is an arithmetic number, because the mean of its divisors is an integer number (6552021605101).
Almost surely, 213104043210201 is an apocalyptic number.
It is an amenable number.
13104043210201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104043210201 is an equidigital number, since it uses as much as digits as its factorization.
13104043210201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13104043210201 its reverse (10201234040131), we get a palindrome (23305277250332).
The spelling of 13104043210201 in words is "thirteen trillion, one hundred four billion, forty-three million, two hundred ten thousand, two hundred one".
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