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131041303202023 = 280346750375741
BaseRepresentation
bin11101110010111001101110…
…010101000000100011100111
3122011222102111201200202211221
4131302321232111000203213
5114133440042104431043
61142411313231241211
736413264436656224
oct3562715625004347
9564872451622757
10131041303202023
1138832339466125
1212844823379207
1358171ac8bc826
14245060bcc894b
151023a41e1a8ed
hex772e6e5408e7

131041303202023 has 4 divisors (see below), whose sum is σ = 131088053580568. Its totient is φ = 130994552823480.

The previous prime is 131041303202011. The next prime is 131041303202059. The reversal of 131041303202023 is 320202303140131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131041303202023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131041303202083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23375185068 + ... + 23375190673.

It is an arithmetic number, because the mean of its divisors is an integer number (32772013395142).

Almost surely, 2131041303202023 is an apocalyptic number.

131041303202023 is a deficient number, since it is larger than the sum of its proper divisors (46750378545).

131041303202023 is an equidigital number, since it uses as much as digits as its factorization.

131041303202023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46750378544.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131041303202023 its reverse (320202303140131), we get a palindrome (451243606342154).

The spelling of 131041303202023 in words is "one hundred thirty-one trillion, forty-one billion, three hundred three million, two hundred two thousand, twenty-three".

Divisors: 1 2803 46750375741 131041303202023