Base | Representation |
---|---|
bin | 11101110010111001101110… |
… | …010101000000100011100111 |
3 | 122011222102111201200202211221 |
4 | 131302321232111000203213 |
5 | 114133440042104431043 |
6 | 1142411313231241211 |
7 | 36413264436656224 |
oct | 3562715625004347 |
9 | 564872451622757 |
10 | 131041303202023 |
11 | 38832339466125 |
12 | 12844823379207 |
13 | 58171ac8bc826 |
14 | 245060bcc894b |
15 | 1023a41e1a8ed |
hex | 772e6e5408e7 |
131041303202023 has 4 divisors (see below), whose sum is σ = 131088053580568. Its totient is φ = 130994552823480.
The previous prime is 131041303202011. The next prime is 131041303202059. The reversal of 131041303202023 is 320202303140131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131041303202023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131041303202083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23375185068 + ... + 23375190673.
It is an arithmetic number, because the mean of its divisors is an integer number (32772013395142).
Almost surely, 2131041303202023 is an apocalyptic number.
131041303202023 is a deficient number, since it is larger than the sum of its proper divisors (46750378545).
131041303202023 is an equidigital number, since it uses as much as digits as its factorization.
131041303202023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46750378544.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131041303202023 its reverse (320202303140131), we get a palindrome (451243606342154).
The spelling of 131041303202023 in words is "one hundred thirty-one trillion, forty-one billion, three hundred three million, two hundred two thousand, twenty-three".
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