Base | Representation |
---|---|
bin | 1011111010110000101110… |
… | …1111110110001100110001 |
3 | 1201101202002012122010200002 |
4 | 2332230023233312030301 |
5 | 3204144240412442431 |
6 | 43511543155435345 |
7 | 2521512601554101 |
oct | 276541357661461 |
9 | 51352065563602 |
10 | 13104142312241 |
11 | 41a2487790342 |
12 | 15778068b5b55 |
13 | 74093b726196 |
14 | 33435b283201 |
15 | 17ad073a83cb |
hex | beb0bbf6331 |
13104142312241 has 2 divisors, whose sum is σ = 13104142312242. Its totient is φ = 13104142312240.
The previous prime is 13104142312193. The next prime is 13104142312253. The reversal of 13104142312241 is 14221324140131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7807106574400 + 5297035737841 = 2794120^2 + 2301529^2 .
It is an emirp because it is prime and its reverse (14221324140131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104142312241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104142312841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552071156120 + 6552071156121.
It is an arithmetic number, because the mean of its divisors is an integer number (6552071156121).
Almost surely, 213104142312241 is an apocalyptic number.
It is an amenable number.
13104142312241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104142312241 is an equidigital number, since it uses as much as digits as its factorization.
13104142312241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 13104142312241 its reverse (14221324140131), we get a palindrome (27325466452372).
The spelling of 13104142312241 in words is "thirteen trillion, one hundred four billion, one hundred forty-two million, three hundred twelve thousand, two hundred forty-one".
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