Base | Representation |
---|---|
bin | 1011111010110000111111… |
… | …0111011100100110011010 |
3 | 1201101202021000122211122100 |
4 | 2332230033313130212122 |
5 | 3204144411110212102 |
6 | 43511554104504230 |
7 | 2521514401115154 |
oct | 276541767344632 |
9 | 51352230584570 |
10 | 13104211413402 |
11 | 41a251279803a |
12 | 1577825a7b076 |
13 | 74094cb3b845 |
14 | 33436650dad4 |
15 | 17ad0d4a7a1c |
hex | beb0fddc99a |
13104211413402 has 48 divisors (see below), whose sum is σ = 29085581528640. Its totient is φ = 4261440667200.
The previous prime is 13104211413367. The next prime is 13104211413481. The reversal of 13104211413402 is 20431411240131.
It is a happy number.
13104211413402 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 211 + 41 + 3 + 402 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39918049 + ... + 40244987.
It is an arithmetic number, because the mean of its divisors is an integer number (605949615180).
Almost surely, 213104211413402 is an apocalyptic number.
13104211413402 is an abundant number, since it is smaller than the sum of its proper divisors (15981370115238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104211413402 is a wasteful number, since it uses less digits than its factorization.
13104211413402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 381299 (or 381296 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 13104211413402 its reverse (20431411240131), we get a palindrome (33535622653533).
The spelling of 13104211413402 in words is "thirteen trillion, one hundred four billion, two hundred eleven million, four hundred thirteen thousand, four hundred two".
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