Base | Representation |
---|---|
bin | 10011000100011011001… |
… | …100001101100100001011 |
3 | 11122021102111200211202212 |
4 | 103010123030031210023 |
5 | 132432220312231103 |
6 | 2441555454215335 |
7 | 163450313341043 |
oct | 23043314154413 |
9 | 4567374624685 |
10 | 1310421211403 |
11 | 46582367a5a7 |
12 | 191b754b454b |
13 | 96759141b15 |
14 | 475d3634723 |
15 | 24148c867d8 |
hex | 1311b30d90b |
1310421211403 has 2 divisors, whose sum is σ = 1310421211404. Its totient is φ = 1310421211402.
The previous prime is 1310421211391. The next prime is 1310421211423. The reversal of 1310421211403 is 3041121240131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310421211403 - 220 = 1310420162827 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310421211423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655210605701 + 655210605702.
It is an arithmetic number, because the mean of its divisors is an integer number (655210605702).
Almost surely, 21310421211403 is an apocalyptic number.
1310421211403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310421211403 is an equidigital number, since it uses as much as digits as its factorization.
1310421211403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1310421211403 its reverse (3041121240131), we get a palindrome (4351542451534).
The spelling of 1310421211403 in words is "one trillion, three hundred ten billion, four hundred twenty-one million, two hundred eleven thousand, four hundred three".
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