Base | Representation |
---|---|
bin | 10011000100011011001… |
… | …100100110100111111100 |
3 | 11122021102111220001120101 |
4 | 103010123030212213330 |
5 | 132432220324022134 |
6 | 2441555500330444 |
7 | 163450314246223 |
oct | 23043314464774 |
9 | 4567374801511 |
10 | 1310421314044 |
11 | 46582373a727 |
12 | 191b75543a24 |
13 | 9675917975b |
14 | 475d365dcba |
15 | 24148ca6e14 |
hex | 1311b3269fc |
1310421314044 has 6 divisors (see below), whose sum is σ = 2293237299584. Its totient is φ = 655210657020.
The previous prime is 1310421314039. The next prime is 1310421314047. The reversal of 1310421314044 is 4404131240131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310421314047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 163802664252 + ... + 163802664259.
Almost surely, 21310421314044 is an apocalyptic number.
It is an amenable number.
1310421314044 is a deficient number, since it is larger than the sum of its proper divisors (982815985540).
1310421314044 is a wasteful number, since it uses less digits than its factorization.
1310421314044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 327605328515 (or 327605328513 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1310421314044 its reverse (4404131240131), we get a palindrome (5714552554175).
The spelling of 1310421314044 in words is "one trillion, three hundred ten billion, four hundred twenty-one million, three hundred fourteen thousand, forty-four".
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