Base | Representation |
---|---|
bin | 11101110010111010100100… |
… | …000001011011101110111100 |
3 | 122011222111211111210002102001 |
4 | 131302322210001123232330 |
5 | 114133443413213240444 |
6 | 1142411542451312044 |
7 | 36413325655655326 |
oct | 3562724401335674 |
9 | 564874744702361 |
10 | 131042204040124 |
11 | 38832760a10123 |
12 | 12844a34bab624 |
13 | 58172c441a820 |
14 | 24506957c2616 |
15 | 1023a960608d4 |
hex | 772ea405bbbc |
131042204040124 has 12 divisors (see below), whose sum is σ = 246964153768024. Its totient is φ = 60481017249264.
The previous prime is 131042204040119. The next prime is 131042204040169. The reversal of 131042204040124 is 421040402240131.
It is a junction number, because it is equal to n+sod(n) for n = 131042204040092 and 131042204040101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1260021192642 + ... + 1260021192745.
Almost surely, 2131042204040124 is an apocalyptic number.
It is an amenable number.
131042204040124 is a deficient number, since it is larger than the sum of its proper divisors (115921949727900).
131042204040124 is a wasteful number, since it uses less digits than its factorization.
131042204040124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2520042385404 (or 2520042385402 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 131042204040124 its reverse (421040402240131), we get a palindrome (552082606280255).
The spelling of 131042204040124 in words is "one hundred thirty-one trillion, forty-two billion, two hundred four million, forty thousand, one hundred twenty-four".
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