Base | Representation |
---|---|
bin | 10011000100011011011… |
… | …010101101110011110001 |
3 | 11122021102202212000020212 |
4 | 103010123122231303301 |
5 | 132432222300412424 |
6 | 2442000111513505 |
7 | 163450360554614 |
oct | 23043332556361 |
9 | 4567382760225 |
10 | 1310425013489 |
11 | 465825837119 |
12 | 191b76828895 |
13 | 96759b73587 |
14 | 475d3d4417b |
15 | 2414928810e |
hex | 1311b6adcf1 |
1310425013489 has 2 divisors, whose sum is σ = 1310425013490. Its totient is φ = 1310425013488.
The previous prime is 1310425013407. The next prime is 1310425013519. The reversal of 1310425013489 is 9843105240131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 842797441600 + 467627571889 = 918040^2 + 683833^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310425013489 - 212 = 1310425009393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310425313489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655212506744 + 655212506745.
It is an arithmetic number, because the mean of its divisors is an integer number (655212506745).
Almost surely, 21310425013489 is an apocalyptic number.
It is an amenable number.
1310425013489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310425013489 is an equidigital number, since it uses as much as digits as its factorization.
1310425013489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 41.
The spelling of 1310425013489 in words is "one trillion, three hundred ten billion, four hundred twenty-five million, thirteen thousand, four hundred eighty-nine".
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