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13104251 is a prime number
BaseRepresentation
bin110001111111…
…010001111011
3220122202122122
4301333101323
511323314001
61144511455
7216245546
oct61772173
926582578
1013104251
117440466
12447b58b
13293a7c4
141a5185d
15123cb1b
hexc7f47b

13104251 has 2 divisors, whose sum is σ = 13104252. Its totient is φ = 13104250.

The previous prime is 13104209. The next prime is 13104269. The reversal of 13104251 is 15240131.

It is a strong prime.

It is an emirp because it is prime and its reverse (15240131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13104251 - 218 = 12842107 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13104151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552125 + 6552126.

It is an arithmetic number, because the mean of its divisors is an integer number (6552126).

Almost surely, 213104251 is an apocalyptic number.

13104251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104251 is an equidigital number, since it uses as much as digits as its factorization.

13104251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 13104251 is about 3619.9794198310. The cubic root of 13104251 is about 235.7603319550.

Adding to 13104251 its reverse (15240131), we get a palindrome (28344382).

The spelling of 13104251 in words is "thirteen million, one hundred four thousand, two hundred fifty-one".